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HexStr: don't build a vector<char> first

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Also const correctness for lookup tables in hex functions throughout the code.
This commit is contained in:
Wladimir J. van der Laan
2012-09-09 14:52:07 +02:00
parent 963af6449f
commit ac4e7f6269
4 changed files with 7 additions and 7 deletions
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8
src/util.h
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@@ -256,9 +256,9 @@ inline int64 abs64(int64 n)
template<typename T>
std::string HexStr(const T itbegin, const T itend, bool fSpaces=false)
{
std::vector<char> rv;
static char hexmap[16] = { '0', '1', '2', '3', '4', '5', '6', '7',
'8', '9', 'a', 'b', 'c', 'd', 'e', 'f' };
std::string rv;
static const char hexmap[16] = { '0', '1', '2', '3', '4', '5', '6', '7',
'8', '9', 'a', 'b', 'c', 'd', 'e', 'f' };
rv.reserve((itend-itbegin)*3);
for(T it = itbegin; it < itend; ++it)
{
@@ -269,7 +269,7 @@ std::string HexStr(const T itbegin, const T itend, bool fSpaces=false)
rv.push_back(hexmap[val&15]);
}
return std::string(rv.begin(), rv.end());
return rv;
}
inline std::string HexStr(const std::vector<unsigned char>& vch, bool fSpaces=false)