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https://github.com/lightningnetwork/lnd.git
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sweep: simplify polling logic in sweeper
This commit attempts to make the polling logic in sweeper more linear. Previously, the sweep's timer is reset/restarted in multiple places, such as when a new input comes in, or a new block comes in, or a previous input being spent, making it difficult to follow. We now remove the old timer and replaces it with a simple polling logic - we will schedule sweeps every 5s(default), and if there's no input to be swept, we'd skip, just like the previous `scheduleSweep` does. It's also worthy noting that, although `scheduleSweep` triggers the timer to tick, by the time we do the actual sweep in `sweepCluster`, conditions may have changed. This is now also fixed because we only have one place to create the clusters and sweeps.
This commit is contained in:
@ -4,7 +4,6 @@ import (
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"errors"
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"os"
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"reflect"
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"runtime/debug"
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"runtime/pprof"
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"sort"
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"testing"
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@ -44,7 +43,6 @@ type sweeperTestContext struct {
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backend *mockBackend
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store *MockSweeperStore
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timeoutChan chan chan time.Time
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publishChan chan wire.MsgTx
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}
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@ -123,7 +121,6 @@ func createSweeperTestContext(t *testing.T) *sweeperTestContext {
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estimator: estimator,
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backend: backend,
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store: store,
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timeoutChan: make(chan chan time.Time, 1),
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}
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ctx.sweeper = New(&UtxoSweeperConfig{
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@ -163,43 +160,6 @@ func (ctx *sweeperTestContext) restartSweeper() {
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ctx.sweeper.Start()
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}
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func (ctx *sweeperTestContext) tick() {
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testLog.Trace("Waiting for tick to be consumed")
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select {
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case c := <-ctx.timeoutChan:
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select {
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case c <- time.Time{}:
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testLog.Trace("Tick")
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case <-time.After(defaultTestTimeout):
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debug.PrintStack()
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ctx.t.Fatal("tick timeout - tick not consumed")
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}
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case <-time.After(defaultTestTimeout):
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debug.PrintStack()
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ctx.t.Fatal("tick timeout - no new timer created")
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}
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}
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// assertNoTick asserts that the sweeper does not wait for a tick.
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func (ctx *sweeperTestContext) assertNoTick() {
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ctx.t.Helper()
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select {
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case <-ctx.timeoutChan:
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ctx.t.Fatal("unexpected tick")
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case <-time.After(processingDelay):
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}
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}
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func (ctx *sweeperTestContext) assertNoNewTimer() {
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select {
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case <-ctx.timeoutChan:
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ctx.t.Fatal("no new timer expected")
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default:
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}
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}
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func (ctx *sweeperTestContext) finish(expectedGoroutineCount int) {
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// We assume that when finish is called, sweeper has finished all its
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// goroutines. This implies that the waitgroup is empty.
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@ -233,7 +193,6 @@ func (ctx *sweeperTestContext) finish(expectedGoroutineCount int) {
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// We should have consumed and asserted all published transactions in
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// our unit tests.
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ctx.assertNoTx()
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ctx.assertNoNewTimer()
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if !ctx.backend.isDone() {
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ctx.t.Fatal("unconfirmed txes remaining")
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}
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@ -383,8 +342,6 @@ func TestSuccess(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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sweepTx := ctx.receiveTx()
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ctx.backend.mine()
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@ -437,8 +394,6 @@ func TestDust(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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// The second input brings the sweep output above the dust limit. We
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// expect a sweep tx now.
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@ -478,8 +433,6 @@ func TestWalletUtxo(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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sweepTx := ctx.receiveTx()
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if len(sweepTx.TxIn) != 2 {
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t.Fatalf("Expected tx to sweep 2 inputs, but contains %v "+
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@ -532,8 +485,6 @@ func TestNegativeInput(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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// We expect that a sweep tx is published now, but it should only
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// contain the large input. The negative input should stay out of sweeps
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// until fees come down to get a positive net yield.
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@ -557,8 +508,6 @@ func TestNegativeInput(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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sweepTx2 := ctx.receiveTx()
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assertTxSweepsInputs(t, &sweepTx2, &secondLargeInput, &negInput)
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@ -582,8 +531,6 @@ func TestChunks(t *testing.T) {
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}
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}
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ctx.tick()
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// We expect two txes to be published because of the max input count of
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// three.
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sweepTx1 := ctx.receiveTx()
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@ -645,7 +592,6 @@ func testRemoteSpend(t *testing.T, postSweep bool) {
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}
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if postSweep {
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ctx.tick()
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// Tx publication by sweeper returns ErrDoubleSpend. Sweeper
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// will retry the inputs without reporting a result. It could be
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@ -669,7 +615,6 @@ func testRemoteSpend(t *testing.T, postSweep bool) {
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if !postSweep {
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// Assert that the sweeper sweeps the remaining input.
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ctx.tick()
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sweepTx := ctx.receiveTx()
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if len(sweepTx.TxIn) != 1 {
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@ -710,8 +655,6 @@ func TestIdempotency(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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ctx.receiveTx()
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resultChan3, err := ctx.sweeper.SweepInput(input, defaultFeePref)
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@ -739,7 +682,6 @@ func TestIdempotency(t *testing.T) {
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// Timer is still running, but spend notification was delivered before
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// it expired.
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ctx.tick()
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ctx.finish(1)
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}
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@ -762,7 +704,6 @@ func TestRestart(t *testing.T) {
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if _, err := ctx.sweeper.SweepInput(input1, defaultFeePref); err != nil {
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t.Fatal(err)
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}
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ctx.tick()
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ctx.receiveTx()
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@ -798,8 +739,6 @@ func TestRestart(t *testing.T) {
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// Timer tick should trigger republishing a sweep for the remaining
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// input.
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ctx.tick()
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ctx.receiveTx()
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ctx.backend.mine()
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@ -837,8 +776,6 @@ func TestRestartRemoteSpend(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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sweepTx := ctx.receiveTx()
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// Restart sweeper.
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@ -869,8 +806,6 @@ func TestRestartRemoteSpend(t *testing.T) {
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// Expect sweeper to construct a new tx, because input 1 was spend
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// remotely.
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ctx.tick()
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ctx.receiveTx()
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ctx.backend.mine()
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@ -891,8 +826,6 @@ func TestRestartConfirmed(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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ctx.receiveTx()
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// Restart sweeper.
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@ -910,9 +843,6 @@ func TestRestartConfirmed(t *testing.T) {
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// Here we expect again a successful sweep.
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ctx.expectResult(spendChan, nil)
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// Timer started but not needed because spend ntfn was sent.
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ctx.tick()
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ctx.finish(1)
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}
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@ -927,8 +857,6 @@ func TestRetry(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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// We expect a sweep to be published.
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ctx.receiveTx()
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@ -944,8 +872,6 @@ func TestRetry(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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// Two txes are expected to be published, because new and retry inputs
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// are separated.
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ctx.receiveTx()
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@ -971,8 +897,6 @@ func TestGiveUp(t *testing.T) {
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t.Fatal(err)
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}
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ctx.tick()
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// We expect a sweep to be published at height 100 (mockChainIOHeight).
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ctx.receiveTx()
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@ -983,12 +907,10 @@ func TestGiveUp(t *testing.T) {
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// Second attempt
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ctx.notifier.NotifyEpoch(101)
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ctx.tick()
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ctx.receiveTx()
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// Third attempt
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ctx.notifier.NotifyEpoch(103)
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ctx.tick()
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ctx.receiveTx()
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ctx.expectResult(resultChan0, ErrTooManyAttempts)
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@ -1038,10 +960,6 @@ func TestDifferentFeePreferences(t *testing.T) {
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t.Fatal(err)
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}
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// Start the sweeper's batch ticker, which should cause the sweep
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// transactions to be broadcast in order of high to low fee preference.
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ctx.tick()
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// Generate the same type of sweep script that was used for weight
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// estimation.
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changePk, err := ctx.sweeper.cfg.GenSweepScript()
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@ -1121,7 +1039,6 @@ func TestPendingInputs(t *testing.T) {
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// rate sweep to ensure we can detect pending inputs after a sweep.
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// Once the higher fee rate sweep confirms, we should no longer see
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// those inputs pending.
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ctx.tick()
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ctx.receiveTx()
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lowFeeRateTx := ctx.receiveTx()
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ctx.backend.deleteUnconfirmed(lowFeeRateTx.TxHash())
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@ -1133,7 +1050,6 @@ func TestPendingInputs(t *testing.T) {
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// sweep. Once again we'll ensure those inputs are no longer pending
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// once the sweep transaction confirms.
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ctx.backend.notifier.NotifyEpoch(101)
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ctx.tick()
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ctx.receiveTx()
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ctx.backend.mine()
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ctx.expectResult(resultChan3, nil)
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@ -1179,7 +1095,6 @@ func TestBumpFeeRBF(t *testing.T) {
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require.NoError(t, err)
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// Ensure that a transaction is broadcast with the lower fee preference.
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ctx.tick()
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lowFeeTx := ctx.receiveTx()
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assertTxFeeRate(t, &lowFeeTx, lowFeeRate, changePk, &input)
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@ -1200,7 +1115,6 @@ func TestBumpFeeRBF(t *testing.T) {
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require.NoError(t, err, "unable to bump input's fee")
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// A higher fee rate transaction should be immediately broadcast.
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ctx.tick()
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highFeeTx := ctx.receiveTx()
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assertTxFeeRate(t, &highFeeTx, highFeeRate, changePk, &input)
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@ -1234,7 +1148,6 @@ func TestExclusiveGroup(t *testing.T) {
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// We expect all inputs to be published in separate transactions, even
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// though they share the same fee preference.
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ctx.tick()
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for i := 0; i < 3; i++ {
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sweepTx := ctx.receiveTx()
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if len(sweepTx.TxOut) != 1 {
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@ -1306,10 +1219,6 @@ func TestCpfp(t *testing.T) {
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)
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require.NoError(t, err)
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// Because we sweep at 1000 sat/kw, the parent cannot be paid for. We
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// expect the sweeper to remain idle.
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ctx.assertNoTick()
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// Increase the fee estimate to above the parent tx fee rate.
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ctx.estimator.updateFees(5000, chainfee.FeePerKwFloor)
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@ -1319,7 +1228,6 @@ func TestCpfp(t *testing.T) {
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// Now we do expect a sweep transaction to be published with our input
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// and an attached wallet utxo.
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ctx.tick()
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tx := ctx.receiveTx()
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require.Len(t, tx.TxIn, 2)
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require.Len(t, tx.TxOut, 1)
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@ -1691,10 +1599,6 @@ func TestLockTimes(t *testing.T) {
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inputs[*op] = inp
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}
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// We expect all inputs to be published in separate transactions, even
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// though they share the same fee preference.
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ctx.tick()
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// Check the sweeps transactions, ensuring all inputs are there, and
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// all the locktimes are satisfied.
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for i := 0; i < numSweeps; i++ {
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@ -2139,9 +2043,6 @@ func TestRequiredTxOuts(t *testing.T) {
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inputs[*op] = inp
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}
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// Tick, which should trigger a sweep of all inputs.
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ctx.tick()
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// Check the sweeps transactions, ensuring all inputs
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// are there, and all the locktimes are satisfied.
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var sweeps []*wire.MsgTx
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