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validated input where invalid number is entered in menu()

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vishalxl 2022-08-14 00:17:09 +05:30
parent 1d21ce6679
commit 53303b075d
1 changed files with 10 additions and 8 deletions
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18
bin/nostr_console.dart
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@ -51,14 +51,16 @@ int showMenu(List<String> menuOptions) {
String? userOptionInput = stdin.readLineSync();
String userOption = userOptionInput??"";
//print("read option $userOption");
if( !int.parse(userOption).isNaN) {
int valueOption = int.parse(userOption);
if( valueOption < 1 || valueOption > menuOptions.length) {
print("Invalid option. Kindly try again.\n");
continue;
} else {
if( int.tryParse(userOption) != null) {
int? valueOption = int.tryParse(userOption);
if( valueOption != null) {
if( valueOption < 1 || valueOption > menuOptions.length) {
print("Invalid option. Kindly try again.\n");
continue;
} else {
return valueOption;
return valueOption;
}
}
} else {
print("Invalid option. Kindly try again.\n");
@ -78,7 +80,7 @@ Future<void> terminalMenuUi(Tree node, var contactList) async {
bool userContinue = true;
while(userContinue) {
print('\nPick an option by typing the correspoinding\nnumber and then pressing <enter>:');
print('\nPick an option by typing the corresponding\nnumber and then pressing <enter>:');
int option = showMenu(['Display events', // 1
'Post/Reply', // 2
'Exit']); // 3