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descriptors: Change Parse to return vector of descriptors

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When given a descriptor which contins a multipath derivation specifier,
a vector of descriptors will be returned.
This commit is contained in:
Ava Chow
2024-08-07 16:29:06 -04:00
parent 0d640c6f02
commit 1bbf46e2da
22 changed files with 178 additions and 111 deletions
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15
src/script/descriptor.cpp
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@@ -2364,14 +2364,21 @@ bool CheckChecksum(Span<const char>& sp, bool require_checksum, std::string& err
return true;
}
std::unique_ptr<Descriptor> Parse(const std::string& descriptor, FlatSigningProvider& out, std::string& error, bool require_checksum)
std::vector<std::unique_ptr<Descriptor>> Parse(const std::string& descriptor, FlatSigningProvider& out, std::string& error, bool require_checksum)
{
Span<const char> sp{descriptor};
if (!CheckChecksum(sp, require_checksum, error)) return nullptr;
if (!CheckChecksum(sp, require_checksum, error)) return {};
uint32_t key_exp_index = 0;
auto ret = ParseScript(key_exp_index, sp, ParseScriptContext::TOP, out, error);
if (sp.size() == 0 && !ret.empty()) return std::unique_ptr<Descriptor>(std::move(ret.at(0)));
return nullptr;
if (sp.size() == 0 && !ret.empty()) {
std::vector<std::unique_ptr<Descriptor>> descs;
descs.reserve(ret.size());
for (auto& r : ret) {
descs.emplace_back(std::unique_ptr<Descriptor>(std::move(r)));
}
return descs;
}
return {};
}
std::string GetDescriptorChecksum(const std::string& descriptor)