Make signing follow BIP340 exactly w.r.t. aux randomness

libsecp256k1's secp256k1_schnorrsig_sign only follows BIP340 exactly
if an aux_rand32 argument is passed. When no randomness is used
(as is the case in the current codebase here), there is no impact
on security between not providing aux_rand32 at all, or providing
an empty one. Yet, for repeatability/testability it is simpler
to always use an all-zero one.
This commit is contained in:
Pieter Wuille
2021-10-28 13:46:52 -04:00
parent c9dd5c8d6e
commit 2478c6730a
4 changed files with 8 additions and 7 deletions

View File

@@ -321,7 +321,7 @@ BOOST_AUTO_TEST_CASE(bip340_test_vectors)
key.Set(sec.begin(), sec.end(), true);
XOnlyPubKey pubkey(key.GetPubKey());
BOOST_CHECK(std::equal(pubkey.begin(), pubkey.end(), pub.begin(), pub.end()));
bool ok = key.SignSchnorr(msg256, sig64, nullptr, &aux256);
bool ok = key.SignSchnorr(msg256, sig64, nullptr, aux256);
BOOST_CHECK(ok);
BOOST_CHECK(std::vector<unsigned char>(sig64, sig64 + 64) == sig);
// Verify those signatures for good measure.
@@ -337,7 +337,7 @@ BOOST_AUTO_TEST_CASE(bip340_test_vectors)
BOOST_CHECK(tweaked);
XOnlyPubKey tweaked_key = tweaked->first;
aux256 = InsecureRand256();
bool ok = key.SignSchnorr(msg256, sig64, &merkle_root, &aux256);
bool ok = key.SignSchnorr(msg256, sig64, &merkle_root, aux256);
BOOST_CHECK(ok);
BOOST_CHECK(tweaked_key.VerifySchnorr(msg256, sig64));
}