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test: replace (send_message + sync_with_ping) with send_and_ping
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@ -94,8 +94,7 @@ class MaxUploadTest(BitcoinTestFramework):
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# 576MB will be reserved for relaying new blocks, so expect this to
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# succeed for ~235 tries.
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for i in range(success_count):
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p2p_conns[0].send_message(getdata_request)
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p2p_conns[0].sync_with_ping()
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p2p_conns[0].send_and_ping(getdata_request)
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assert_equal(p2p_conns[0].block_receive_map[big_old_block], i+1)
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assert_equal(len(self.nodes[0].getpeerinfo()), 3)
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@ -112,8 +111,7 @@ class MaxUploadTest(BitcoinTestFramework):
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# We'll try 800 times
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getdata_request.inv = [CInv(2, big_new_block)]
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for i in range(800):
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p2p_conns[1].send_message(getdata_request)
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p2p_conns[1].sync_with_ping()
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p2p_conns[1].send_and_ping(getdata_request)
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assert_equal(p2p_conns[1].block_receive_map[big_new_block], i+1)
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self.log.info("Peer 1 able to repeatedly download new block")
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@ -132,8 +130,7 @@ class MaxUploadTest(BitcoinTestFramework):
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# and p2p_conns[2] should be able to retrieve the old block.
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self.nodes[0].setmocktime(int(time.time()))
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p2p_conns[2].sync_with_ping()
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p2p_conns[2].send_message(getdata_request)
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p2p_conns[2].sync_with_ping()
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p2p_conns[2].send_and_ping(getdata_request)
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assert_equal(p2p_conns[2].block_receive_map[big_old_block], 1)
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self.log.info("Peer 2 able to download old block")
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@ -150,8 +147,7 @@ class MaxUploadTest(BitcoinTestFramework):
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#retrieve 20 blocks which should be enough to break the 1MB limit
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getdata_request.inv = [CInv(2, big_new_block)]
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for i in range(20):
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self.nodes[0].p2p.send_message(getdata_request)
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self.nodes[0].p2p.sync_with_ping()
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self.nodes[0].p2p.send_and_ping(getdata_request)
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assert_equal(self.nodes[0].p2p.block_receive_map[big_new_block], i+1)
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getdata_request.inv = [CInv(2, big_old_block)]
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