highperfocused/bitcoin
1
0
Fork 0
mirror of https://github.com/bitcoin/bitcoin.git synced 2025-12-04 17:52:25 +01:00
Code Issues Packages Projects Releases Wiki Activity

wallet/rpc: add maxfeerate parameter to sendrawtransaction

Browse Source
This commit is contained in:
Karl-Johan Alm
2018-06-27 17:21:07 +09:00
parent e5efacb941
commit 6c0a6f73e3
13 changed files with 126 additions and 70 deletions
Download Patch File Download Diff File Expand all files Collapse all files

76
test/functional/feature_rbf.py
View File

@@ -46,7 +46,7 @@ def make_utxo(node, amount, confirmed=True, scriptPubKey=CScript([1])):
signed_tx = node.signrawtransactionwithwallet(txToHex(tx2))
txid = node.sendrawtransaction(signed_tx['hex'], True)
txid = node.sendrawtransaction(signed_tx['hex'], 0)
# If requested, ensure txouts are confirmed.
if confirmed:
@@ -136,7 +136,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))]
tx1a_hex = txToHex(tx1a)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, 0)
self.sync_all()
@@ -147,9 +147,9 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1b_hex = txToHex(tx1b)
# This will raise an exception due to insufficient fee
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, True)
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, 0)
# This will raise an exception due to transaction replacement being disabled
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[1].sendrawtransaction, tx1b_hex, True)
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[1].sendrawtransaction, tx1b_hex, 0)
# Extra 0.1 BTC fee
tx1b = CTransaction()
@@ -157,9 +157,9 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1b.vout = [CTxOut(int(0.9 * COIN), CScript([b'b' * 35]))]
tx1b_hex = txToHex(tx1b)
# Replacement still disabled even with "enough fee"
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[1].sendrawtransaction, tx1b_hex, True)
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[1].sendrawtransaction, tx1b_hex, 0)
# Works when enabled
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, 0)
mempool = self.nodes[0].getrawmempool()
@@ -188,7 +188,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx.vin = [CTxIn(prevout, nSequence=0)]
tx.vout = [CTxOut(remaining_value, CScript([1, OP_DROP] * 15 + [1]))]
tx_hex = txToHex(tx)
txid = self.nodes[0].sendrawtransaction(tx_hex, True)
txid = self.nodes[0].sendrawtransaction(tx_hex, 0)
chain_txids.append(txid)
prevout = COutPoint(int(txid, 16), 0)
@@ -200,14 +200,14 @@ class ReplaceByFeeTest(BitcoinTestFramework):
dbl_tx_hex = txToHex(dbl_tx)
# This will raise an exception due to insufficient fee
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, True)
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, 0)
# Accepted with sufficient fee
dbl_tx = CTransaction()
dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
dbl_tx.vout = [CTxOut(1 * COIN, CScript([1] * 35))]
dbl_tx_hex = txToHex(dbl_tx)
self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
self.nodes[0].sendrawtransaction(dbl_tx_hex, 0)
mempool = self.nodes[0].getrawmempool()
for doublespent_txid in chain_txids:
@@ -237,7 +237,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx_hex = txToHex(tx)
assert len(tx.serialize()) < 100000
txid = self.nodes[0].sendrawtransaction(tx_hex, True)
txid = self.nodes[0].sendrawtransaction(tx_hex, 0)
yield tx
_total_txs[0] += 1
@@ -261,14 +261,14 @@ class ReplaceByFeeTest(BitcoinTestFramework):
dbl_tx.vout = [CTxOut(initial_nValue - fee * n, CScript([1] * 35))]
dbl_tx_hex = txToHex(dbl_tx)
# This will raise an exception due to insufficient fee
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, True)
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, dbl_tx_hex, 0)
# 1 BTC fee is enough
dbl_tx = CTransaction()
dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
dbl_tx.vout = [CTxOut(initial_nValue - fee * n - 1 * COIN, CScript([1] * 35))]
dbl_tx_hex = txToHex(dbl_tx)
self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
self.nodes[0].sendrawtransaction(dbl_tx_hex, 0)
mempool = self.nodes[0].getrawmempool()
@@ -289,7 +289,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
dbl_tx.vout = [CTxOut(initial_nValue - 2 * fee * n, CScript([1] * 35))]
dbl_tx_hex = txToHex(dbl_tx)
# This will raise an exception
assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, dbl_tx_hex, True)
assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, dbl_tx_hex, 0)
for tx in tree_txs:
tx.rehash()
@@ -303,7 +303,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))]
tx1a_hex = txToHex(tx1a)
self.nodes[0].sendrawtransaction(tx1a_hex, True)
self.nodes[0].sendrawtransaction(tx1a_hex, 0)
# Higher fee, but the fee per KB is much lower, so the replacement is
# rejected.
@@ -313,7 +313,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1b_hex = txToHex(tx1b)
# This will raise an exception due to insufficient fee
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, True)
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, 0)
def test_spends_of_conflicting_outputs(self):
"""Replacements that spend conflicting tx outputs are rejected"""
@@ -324,7 +324,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1a.vin = [CTxIn(utxo1, nSequence=0)]
tx1a.vout = [CTxOut(int(1.1 * COIN), CScript([b'a' * 35]))]
tx1a_hex = txToHex(tx1a)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, 0)
tx1a_txid = int(tx1a_txid, 16)
@@ -336,14 +336,14 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx2_hex = txToHex(tx2)
# This will raise an exception
assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, True)
assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, 0)
# Spend tx1a's output to test the indirect case.
tx1b = CTransaction()
tx1b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)]
tx1b.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))]
tx1b_hex = txToHex(tx1b)
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, 0)
tx1b_txid = int(tx1b_txid, 16)
tx2 = CTransaction()
@@ -353,7 +353,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx2_hex = txToHex(tx2)
# This will raise an exception
assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, True)
assert_raises_rpc_error(-26, "bad-txns-spends-conflicting-tx", self.nodes[0].sendrawtransaction, tx2_hex, 0)
def test_new_unconfirmed_inputs(self):
"""Replacements that add new unconfirmed inputs are rejected"""
@@ -364,7 +364,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1.vin = [CTxIn(confirmed_utxo)]
tx1.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))]
tx1_hex = txToHex(tx1)
self.nodes[0].sendrawtransaction(tx1_hex, True)
self.nodes[0].sendrawtransaction(tx1_hex, 0)
tx2 = CTransaction()
tx2.vin = [CTxIn(confirmed_utxo), CTxIn(unconfirmed_utxo)]
@@ -372,7 +372,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx2_hex = txToHex(tx2)
# This will raise an exception
assert_raises_rpc_error(-26, "replacement-adds-unconfirmed", self.nodes[0].sendrawtransaction, tx2_hex, True)
assert_raises_rpc_error(-26, "replacement-adds-unconfirmed", self.nodes[0].sendrawtransaction, tx2_hex, 0)
def test_too_many_replacements(self):
"""Replacements that evict too many transactions are rejected"""
@@ -394,7 +394,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
splitting_tx.vout = outputs
splitting_tx_hex = txToHex(splitting_tx)
txid = self.nodes[0].sendrawtransaction(splitting_tx_hex, True)
txid = self.nodes[0].sendrawtransaction(splitting_tx_hex, 0)
txid = int(txid, 16)
# Now spend each of those outputs individually
@@ -403,7 +403,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx_i.vin = [CTxIn(COutPoint(txid, i), nSequence=0)]
tx_i.vout = [CTxOut(split_value - fee, CScript([b'a' * 35]))]
tx_i_hex = txToHex(tx_i)
self.nodes[0].sendrawtransaction(tx_i_hex, True)
self.nodes[0].sendrawtransaction(tx_i_hex, 0)
# Now create doublespend of the whole lot; should fail.
# Need a big enough fee to cover all spending transactions and have
@@ -418,14 +418,14 @@ class ReplaceByFeeTest(BitcoinTestFramework):
double_tx_hex = txToHex(double_tx)
# This will raise an exception
assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, double_tx_hex, True)
assert_raises_rpc_error(-26, "too many potential replacements", self.nodes[0].sendrawtransaction, double_tx_hex, 0)
# If we remove an input, it should pass
double_tx = CTransaction()
double_tx.vin = inputs[0:-1]
double_tx.vout = [CTxOut(double_spend_value, CScript([b'a']))]
double_tx_hex = txToHex(double_tx)
self.nodes[0].sendrawtransaction(double_tx_hex, True)
self.nodes[0].sendrawtransaction(double_tx_hex, 0)
def test_opt_in(self):
"""Replacing should only work if orig tx opted in"""
@@ -436,7 +436,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0xffffffff)]
tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))]
tx1a_hex = txToHex(tx1a)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, 0)
# This transaction isn't shown as replaceable
assert_equal(self.nodes[0].getmempoolentry(tx1a_txid)['bip125-replaceable'], False)
@@ -448,7 +448,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1b_hex = txToHex(tx1b)
# This will raise an exception
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx1b_hex, True)
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx1b_hex, 0)
tx1_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
@@ -457,7 +457,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0xfffffffe)]
tx2a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))]
tx2a_hex = txToHex(tx2a)
tx2a_txid = self.nodes[0].sendrawtransaction(tx2a_hex, True)
tx2a_txid = self.nodes[0].sendrawtransaction(tx2a_hex, 0)
# Still shouldn't be able to double-spend
tx2b = CTransaction()
@@ -466,7 +466,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx2b_hex = txToHex(tx2b)
# This will raise an exception
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx2b_hex, True)
assert_raises_rpc_error(-26, "txn-mempool-conflict", self.nodes[0].sendrawtransaction, tx2b_hex, 0)
# Now create a new transaction that spends from tx1a and tx2a
# opt-in on one of the inputs
@@ -481,7 +481,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx3a.vout = [CTxOut(int(0.9*COIN), CScript([b'c'])), CTxOut(int(0.9*COIN), CScript([b'd']))]
tx3a_hex = txToHex(tx3a)
tx3a_txid = self.nodes[0].sendrawtransaction(tx3a_hex, True)
tx3a_txid = self.nodes[0].sendrawtransaction(tx3a_hex, 0)
# This transaction is shown as replaceable
assert_equal(self.nodes[0].getmempoolentry(tx3a_txid)['bip125-replaceable'], True)
@@ -496,10 +496,10 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx3c.vout = [CTxOut(int(0.5 * COIN), CScript([b'f' * 35]))]
tx3c_hex = txToHex(tx3c)
self.nodes[0].sendrawtransaction(tx3b_hex, True)
self.nodes[0].sendrawtransaction(tx3b_hex, 0)
# If tx3b was accepted, tx3c won't look like a replacement,
# but make sure it is accepted anyway
self.nodes[0].sendrawtransaction(tx3c_hex, True)
self.nodes[0].sendrawtransaction(tx3c_hex, 0)
def test_prioritised_transactions(self):
# Ensure that fee deltas used via prioritisetransaction are
@@ -512,7 +512,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))]
tx1a_hex = txToHex(tx1a)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, 0)
# Higher fee, but the actual fee per KB is much lower.
tx1b = CTransaction()
@@ -521,13 +521,13 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx1b_hex = txToHex(tx1b)
# Verify tx1b cannot replace tx1a.
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, True)
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx1b_hex, 0)
# Use prioritisetransaction to set tx1a's fee to 0.
self.nodes[0].prioritisetransaction(txid=tx1a_txid, fee_delta=int(-0.1*COIN))
# Now tx1b should be able to replace tx1a
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, 0)
assert tx1b_txid in self.nodes[0].getrawmempool()
@@ -538,7 +538,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0)]
tx2a.vout = [CTxOut(1 * COIN, CScript([b'a' * 35]))]
tx2a_hex = txToHex(tx2a)
self.nodes[0].sendrawtransaction(tx2a_hex, True)
self.nodes[0].sendrawtransaction(tx2a_hex, 0)
# Lower fee, but we'll prioritise it
tx2b = CTransaction()
@@ -548,13 +548,13 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx2b_hex = txToHex(tx2b)
# Verify tx2b cannot replace tx2a.
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx2b_hex, True)
assert_raises_rpc_error(-26, "insufficient fee", self.nodes[0].sendrawtransaction, tx2b_hex, 0)
# Now prioritise tx2b to have a higher modified fee
self.nodes[0].prioritisetransaction(txid=tx2b.hash, fee_delta=int(0.1*COIN))
# tx2b should now be accepted
tx2b_txid = self.nodes[0].sendrawtransaction(tx2b_hex, True)
tx2b_txid = self.nodes[0].sendrawtransaction(tx2b_hex, 0)
assert tx2b_txid in self.nodes[0].getrawmempool()