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Fix bugs on 'unsigned char' platforms.
In ISO C++, the signedness of 'char' is undefined. On some platforms (e.g. ARM), 'char' is an unsigned type, but some of the code relies on 'char' being signed (as it is on x86). This is indicated by compiler warnings like this: bignum.h: In constructor 'CBigNum::CBigNum(char)': bignum.h:81:59: warning: comparison is always true due to limited range of data type [-Wtype-limits] util.cpp: In function 'bool IsHex(const string&)': util.cpp:427:28: warning: comparison is always false due to limited range of data type [-Wtype-limits] In particular, IsHex erroneously returned true regardless of the input characters, as long as the length of the string was a positive multiple of 2. Note: For testing, it's possible using GCC to force char to be unsigned by adding the -funsigned-char parameter to xCXXFLAGS.
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@@ -425,7 +425,7 @@ bool ParseMoney(const char* pszIn, int64& nRet)
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}
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static char phexdigit[256] =
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static signed char phexdigit[256] =
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{ -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,
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-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,
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-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,
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@@ -461,12 +461,12 @@ vector<unsigned char> ParseHex(const char* psz)
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{
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while (isspace(*psz))
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psz++;
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char c = phexdigit[(unsigned char)*psz++];
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if (c == (char)-1)
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signed char c = phexdigit[(unsigned char)*psz++];
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if (c == (signed char)-1)
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break;
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unsigned char n = (c << 4);
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c = phexdigit[(unsigned char)*psz++];
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if (c == (char)-1)
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if (c == (signed char)-1)
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break;
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n |= c;
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vch.push_back(n);
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