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Merge #18474: test: check that peer is connected when calling sync_*
fac3716b09bb9ee121db629873d9694a95cae942 test: check that peer is connected when calling sync_* (MarcoFalke) Pull request description: Without a connection there is no way to sync, so we can fail early and don't have to wait for the timeout ACKs for top commit: jonatack: ACK fac3716b09bb9 Tree-SHA512: 12f771473c23e152dae4bfb201fadb2c3530cf439de64fea07d048734614543080a5d05c9c36e6e398c6a69c8279f609d34706599571814172a11bcfbea4a3b9
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@ -393,6 +393,7 @@ def connect_nodes(from_connection, node_num):
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# with transaction relaying
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wait_until(lambda: all(peer['version'] != 0 for peer in from_connection.getpeerinfo()))
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def sync_blocks(rpc_connections, *, wait=1, timeout=60):
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"""
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Wait until everybody has the same tip.
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@ -406,9 +407,12 @@ def sync_blocks(rpc_connections, *, wait=1, timeout=60):
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best_hash = [x.getbestblockhash() for x in rpc_connections]
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if best_hash.count(best_hash[0]) == len(rpc_connections):
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return
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# Check that each peer has at least one connection
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assert (all([len(x.getpeerinfo()) for x in rpc_connections]))
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time.sleep(wait)
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raise AssertionError("Block sync timed out:{}".format("".join("\n {!r}".format(b) for b in best_hash)))
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def sync_mempools(rpc_connections, *, wait=1, timeout=60, flush_scheduler=True):
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"""
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Wait until everybody has the same transactions in their memory
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@ -422,6 +426,8 @@ def sync_mempools(rpc_connections, *, wait=1, timeout=60, flush_scheduler=True):
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for r in rpc_connections:
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r.syncwithvalidationinterfacequeue()
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return
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# Check that each peer has at least one connection
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assert (all([len(x.getpeerinfo()) for x in rpc_connections]))
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time.sleep(wait)
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raise AssertionError("Mempool sync timed out:{}".format("".join("\n {!r}".format(m) for m in pool)))
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