Add logic to track pubkeys as watch-only, not just scripts

This commit is contained in:
Matt Corallo
2015-06-10 01:04:08 -07:00
parent d3354c52d7
commit f5813bdd3e
6 changed files with 52 additions and 13 deletions

View File

@@ -6,23 +6,30 @@
#include "keystore.h"
#include "key.h"
#include "pubkey.h"
#include "util.h"
#include <boost/foreach.hpp>
bool CKeyStore::GetPubKey(const CKeyID &address, CPubKey &vchPubKeyOut) const
{
CKey key;
if (!GetKey(address, key))
return false;
vchPubKeyOut = key.GetPubKey();
return true;
}
bool CKeyStore::AddKey(const CKey &key) {
return AddKeyPubKey(key, key.GetPubKey());
}
bool CBasicKeyStore::GetPubKey(const CKeyID &address, CPubKey &vchPubKeyOut) const
{
CKey key;
if (!GetKey(address, key)) {
WatchKeyMap::const_iterator it = mapWatchKeys.find(address);
if (it != mapWatchKeys.end()) {
vchPubKeyOut = it->second;
return true;
}
return false;
}
vchPubKeyOut = key.GetPubKey();
return true;
}
bool CBasicKeyStore::AddKeyPubKey(const CKey& key, const CPubKey &pubkey)
{
LOCK(cs_KeyStore);
@@ -58,10 +65,29 @@ bool CBasicKeyStore::GetCScript(const CScriptID &hash, CScript& redeemScriptOut)
return false;
}
static bool ExtractPubKey(const CScript &dest, CPubKey& pubKeyOut)
{
//TODO: Use Solver to extract this?
CScript::const_iterator pc = dest.begin();
opcodetype opcode;
std::vector<unsigned char> vch;
if (!dest.GetOp(pc, opcode, vch) || vch.size() < 33 || vch.size() > 65)
return false;
pubKeyOut = CPubKey(vch);
if (!pubKeyOut.IsFullyValid())
return false;
if (!dest.GetOp(pc, opcode, vch) || opcode != OP_CHECKSIG || dest.GetOp(pc, opcode, vch))
return false;
return true;
}
bool CBasicKeyStore::AddWatchOnly(const CScript &dest)
{
LOCK(cs_KeyStore);
setWatchOnly.insert(dest);
CPubKey pubKey;
if (ExtractPubKey(dest, pubKey))
mapWatchKeys[pubKey.GetID()] = pubKey;
return true;
}
@@ -69,6 +95,9 @@ bool CBasicKeyStore::RemoveWatchOnly(const CScript &dest)
{
LOCK(cs_KeyStore);
setWatchOnly.erase(dest);
CPubKey pubKey;
if (ExtractPubKey(dest, pubKey))
mapWatchKeys.erase(pubKey.GetID());
return true;
}