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[qa] rpc-tests: Properly use integers, floats

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This commit is contained in:
MarcoFalke
2016-03-20 18:18:32 +01:00
parent fa524d9ddb
commit fa2cea163b
15 changed files with 45 additions and 45 deletions
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50
qa/rpc-tests/replace-by-fee.py
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@@ -119,7 +119,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
def test_simple_doublespend(self):
"""Simple doublespend"""
tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
tx1a = CTransaction()
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
@@ -143,7 +143,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# Extra 0.1 BTC fee
tx1b = CTransaction()
tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1b.vout = [CTxOut(0.9*COIN, CScript([b'b']))]
tx1b.vout = [CTxOut(int(0.9*COIN), CScript([b'b']))]
tx1b_hex = txToHex(tx1b)
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
@@ -235,7 +235,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
_total_txs=_total_txs):
yield x
fee = 0.0001*COIN
fee = int(0.0001*COIN)
n = MAX_REPLACEMENT_LIMIT
tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
assert_equal(len(tree_txs), n)
@@ -268,7 +268,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# Try again, but with more total transactions than the "max txs
# double-spent at once" anti-DoS limit.
for n in (MAX_REPLACEMENT_LIMIT+1, MAX_REPLACEMENT_LIMIT*2):
fee = 0.0001*COIN
fee = int(0.0001*COIN)
tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
assert_equal(len(tree_txs), n)
@@ -291,7 +291,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
def test_replacement_feeperkb(self):
"""Replacement requires fee-per-KB to be higher"""
tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
tx1a = CTransaction()
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
@@ -303,7 +303,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# rejected.
tx1b = CTransaction()
tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1b.vout = [CTxOut(0.001*COIN, CScript([b'a'*999000]))]
tx1b.vout = [CTxOut(int(0.001*COIN), CScript([b'a'*999000]))]
tx1b_hex = txToHex(tx1b)
try:
@@ -315,12 +315,12 @@ class ReplaceByFeeTest(BitcoinTestFramework):
def test_spends_of_conflicting_outputs(self):
"""Replacements that spend conflicting tx outputs are rejected"""
utxo1 = make_utxo(self.nodes[0], 1.2*COIN)
utxo2 = make_utxo(self.nodes[0], 3.0*COIN)
utxo1 = make_utxo(self.nodes[0], int(1.2*COIN))
utxo2 = make_utxo(self.nodes[0], 3*COIN)
tx1a = CTransaction()
tx1a.vin = [CTxIn(utxo1, nSequence=0)]
tx1a.vout = [CTxOut(1.1*COIN, CScript([b'a']))]
tx1a.vout = [CTxOut(int(1.1*COIN), CScript([b'a']))]
tx1a_hex = txToHex(tx1a)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
@@ -343,7 +343,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# Spend tx1a's output to test the indirect case.
tx1b = CTransaction()
tx1b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)]
tx1b.vout = [CTxOut(1.0*COIN, CScript([b'a']))]
tx1b.vout = [CTxOut(1*COIN, CScript([b'a']))]
tx1b_hex = txToHex(tx1b)
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
tx1b_txid = int(tx1b_txid, 16)
@@ -363,12 +363,12 @@ class ReplaceByFeeTest(BitcoinTestFramework):
def test_new_unconfirmed_inputs(self):
"""Replacements that add new unconfirmed inputs are rejected"""
confirmed_utxo = make_utxo(self.nodes[0], 1.1*COIN)
unconfirmed_utxo = make_utxo(self.nodes[0], 0.1*COIN, False)
confirmed_utxo = make_utxo(self.nodes[0], int(1.1*COIN))
unconfirmed_utxo = make_utxo(self.nodes[0], int(0.1*COIN), False)
tx1 = CTransaction()
tx1.vin = [CTxIn(confirmed_utxo)]
tx1.vout = [CTxOut(1.0*COIN, CScript([b'a']))]
tx1.vout = [CTxOut(1*COIN, CScript([b'a']))]
tx1_hex = txToHex(tx1)
tx1_txid = self.nodes[0].sendrawtransaction(tx1_hex, True)
@@ -392,7 +392,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# Start by creating a single transaction with many outputs
initial_nValue = 10*COIN
utxo = make_utxo(self.nodes[0], initial_nValue)
fee = 0.0001*COIN
fee = int(0.0001*COIN)
split_value = int((initial_nValue-fee)/(MAX_REPLACEMENT_LIMIT+1))
actual_fee = initial_nValue - split_value*(MAX_REPLACEMENT_LIMIT+1)
@@ -445,7 +445,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
def test_opt_in(self):
""" Replacing should only work if orig tx opted in """
tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
# Create a non-opting in transaction
tx1a = CTransaction()
@@ -457,7 +457,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# Shouldn't be able to double-spend
tx1b = CTransaction()
tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1b.vout = [CTxOut(0.9*COIN, CScript([b'b']))]
tx1b.vout = [CTxOut(int(0.9*COIN), CScript([b'b']))]
tx1b_hex = txToHex(tx1b)
try:
@@ -468,7 +468,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
print tx1b_txid
assert(False)
tx1_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
tx1_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
# Create a different non-opting in transaction
tx2a = CTransaction()
@@ -480,7 +480,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# Still shouldn't be able to double-spend
tx2b = CTransaction()
tx2b.vin = [CTxIn(tx1_outpoint, nSequence=0)]
tx2b.vout = [CTxOut(0.9*COIN, CScript([b'b']))]
tx2b.vout = [CTxOut(int(0.9*COIN), CScript([b'b']))]
tx2b_hex = txToHex(tx2b)
try:
@@ -500,19 +500,19 @@ class ReplaceByFeeTest(BitcoinTestFramework):
tx3a = CTransaction()
tx3a.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0xffffffff),
CTxIn(COutPoint(tx2a_txid, 0), nSequence=0xfffffffd)]
tx3a.vout = [CTxOut(0.9*COIN, CScript([b'c'])), CTxOut(0.9*COIN, CScript([b'd']))]
tx3a.vout = [CTxOut(int(0.9*COIN), CScript([b'c'])), CTxOut(int(0.9*COIN), CScript([b'd']))]
tx3a_hex = txToHex(tx3a)
self.nodes[0].sendrawtransaction(tx3a_hex, True)
tx3b = CTransaction()
tx3b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)]
tx3b.vout = [CTxOut(0.5*COIN, CScript([b'e']))]
tx3b.vout = [CTxOut(int(0.5*COIN), CScript([b'e']))]
tx3b_hex = txToHex(tx3b)
tx3c = CTransaction()
tx3c.vin = [CTxIn(COutPoint(tx2a_txid, 0), nSequence=0)]
tx3c.vout = [CTxOut(0.5*COIN, CScript([b'f']))]
tx3c.vout = [CTxOut(int(0.5*COIN), CScript([b'f']))]
tx3c_hex = txToHex(tx3c)
self.nodes[0].sendrawtransaction(tx3b_hex, True)
@@ -525,7 +525,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# correctly used by replacement logic
# 1. Check that feeperkb uses modified fees
tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
tx0_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
tx1a = CTransaction()
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
@@ -536,7 +536,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# Higher fee, but the actual fee per KB is much lower.
tx1b = CTransaction()
tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1b.vout = [CTxOut(0.001*COIN, CScript([b'a'*740000]))]
tx1b.vout = [CTxOut(int(0.001*COIN), CScript([b'a'*740000]))]
tx1b_hex = txToHex(tx1b)
# Verify tx1b cannot replace tx1a.
@@ -556,7 +556,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
assert(tx1b_txid in self.nodes[0].getrawmempool())
# 2. Check that absolute fee checks use modified fee.
tx1_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
tx1_outpoint = make_utxo(self.nodes[0], int(1.1*COIN))
tx2a = CTransaction()
tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0)]
@@ -567,7 +567,7 @@ class ReplaceByFeeTest(BitcoinTestFramework):
# Lower fee, but we'll prioritise it
tx2b = CTransaction()
tx2b.vin = [CTxIn(tx1_outpoint, nSequence=0)]
tx2b.vout = [CTxOut(1.01*COIN, CScript([b'a']))]
tx2b.vout = [CTxOut(int(1.01*COIN), CScript([b'a']))]
tx2b.rehash()
tx2b_hex = txToHex(tx2b)