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refactor: Return std::span from MakeUCharSpan
This is possible and safe, because std::span can implicitly convert into Span, if needed.
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@@ -290,9 +290,10 @@ template <typename B>
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concept BasicByte = requires { UCharCast(std::span<B>{}.data()); };
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// Helper function to safely convert a Span to a Span<[const] unsigned char>.
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template <typename T> constexpr auto UCharSpanCast(Span<T> s) -> Span<typename std::remove_pointer<decltype(UCharCast(s.data()))>::type> { return {UCharCast(s.data()), s.size()}; }
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template <typename T, size_t N> constexpr auto UCharSpanCast(std::span<T, N> s) { return std::span<std::remove_pointer_t<decltype(UCharCast(s.data()))>, N>{UCharCast(s.data()), s.size()}; }
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/** Like the Span constructor, but for (const) unsigned char member types only. Only works for (un)signed char containers. */
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template <typename V> constexpr auto MakeUCharSpan(V&& v) -> decltype(UCharSpanCast(Span{std::forward<V>(v)})) { return UCharSpanCast(Span{std::forward<V>(v)}); }
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template <typename V> constexpr auto MakeUCharSpan(const V& v) -> decltype(UCharSpanCast(std::span{v})) { return UCharSpanCast(std::span{v}); }
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template <typename V> constexpr auto MakeWritableUCharSpan(V&& v) -> decltype(UCharSpanCast(std::span{std::forward<V>(v)})) { return UCharSpanCast(std::span{std::forward<V>(v)}); }
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#endif // BITCOIN_SPAN_H
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