Merge bitcoin/bitcoin#32300: feefrac: avoid integer overflow in temporary

5cb1241814 feefrac: avoid integer overflow in temporary (Pieter Wuille)

Pull request description:

  In `FeeFrac::Div(__int128 n, int32_t d, bool round_down)` in src/util/feefrac.h, the following line computes the result:

  ```c++
          return quot + (mod > 0) - (mod && round_down);
  ```

  The function can only be called under conditions where the result is in range, and thus doesn't involve any integer overflow. However, the intermediary result computed by just `quot + (mod > 0)` may still overflow if it's going to be corrected by the `- (mod && round_down)` that follows.

  Fix this by balancing the two correction steps with each other first:
  ```c++
          return quot + ((mod > 0) - (mod && round_down));
  ```

  Fixes #32294.

ACKs for top commit:
  l0rinc:
    Tested ACK 5cb1241814
  maflcko:
    lgtm ACK 5cb1241814
  achow101:
    ACK 5cb1241814

Tree-SHA512: 9daaccdf9acd7652d53b52cad2dc12872558265e863acdde2d6015f885cb87c0505f9bd5be5499fc0a0eded29bec719643f6af1fbc3604518143985094226c95

src/test/feefrac_tests.cpp

@@ -148,6 +148,8 @@ BOOST_AUTO_TEST_CASE(feefrac_operators)
     FeeFrac max_fee2{1, 1};
     BOOST_CHECK(max_fee >= max_fee2);
 
+    // Test for integer overflow issue (https://github.com/bitcoin/bitcoin/issues/32294)
+    BOOST_CHECK_EQUAL((FeeFrac{0x7ffffffdfffffffb, 0x7ffffffd}.EvaluateFeeDown(0x7fffffff)), 0x7fffffffffffffff);
 }
 
 BOOST_AUTO_TEST_SUITE_END()

src/util/feefrac.h

@@ -96,7 +96,7 @@ struct FeeFrac
         int64_t quot = n / d;
         int32_t mod = n % d;
         // Correct result if the / operator above rounded in the wrong direction.
-        return quot + (mod > 0) - (mod && round_down);
+        return quot + ((mod > 0) - (mod && round_down));
     }
 #else
     static constexpr auto Mul = MulFallback;