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Use cluster linearization for transaction relay sort order
Previously, transaction batches were first sorted by ancestor count and then feerate, to ensure transactions are announced in a topologically valid order, while prioritizing higher feerate transactions. Ancestor count is a crude topological sort criteria, so replace this with linearization order so that the highest feerate transactions (as would be observed by the mining algorithm) are relayed before lower feerate ones, in a topologically valid way. This also fixes a test that only worked due to the ancestor-count-based sort order.
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@@ -5425,8 +5425,8 @@ public:
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bool operator()(std::set<Wtxid>::iterator a, std::set<Wtxid>::iterator b)
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{
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/* As std::make_heap produces a max-heap, we want the entries with the
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* fewest ancestors/highest fee to sort later. */
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return m_mempool->CompareDepthAndScore(*b, *a);
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* higher mining score to sort later. */
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return m_mempool->CompareMiningScoreWithTopology(*b, *a);
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}
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};
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} // namespace
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@@ -803,24 +803,20 @@ void CTxMemPool::check(const CCoinsViewCache& active_coins_tip, int64_t spendhei
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assert(innerUsage == cachedInnerUsage);
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}
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bool CTxMemPool::CompareDepthAndScore(const Wtxid& hasha, const Wtxid& hashb) const
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bool CTxMemPool::CompareMiningScoreWithTopology(const Wtxid& hasha, const Wtxid& hashb) const
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{
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/* Return `true` if hasha should be considered sooner than hashb. Namely when:
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* a is not in the mempool, but b is
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* both are in the mempool and a has fewer ancestors than b
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* both are in the mempool and a has a higher score than b
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/* Return `true` if hasha should be considered sooner than hashb, namely when:
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* a is not in the mempool but b is, or
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* both are in the mempool but a is sorted before b in the total mempool ordering
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* (which takes dependencies and (chunk) feerates into account).
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*/
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LOCK(cs);
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auto j{GetIter(hashb)};
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if (!j.has_value()) return false;
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auto i{GetIter(hasha)};
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if (!i.has_value()) return true;
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uint64_t counta = i.value()->GetCountWithAncestors();
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uint64_t countb = j.value()->GetCountWithAncestors();
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if (counta == countb) {
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return CompareTxMemPoolEntryByScore()(*i.value(), *j.value());
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}
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return counta < countb;
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return m_txgraph->CompareMainOrder(*i.value(), *j.value()) < 0;
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}
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namespace {
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@@ -379,7 +379,7 @@ public:
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void removeConflicts(const CTransaction& tx) EXCLUSIVE_LOCKS_REQUIRED(cs);
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void removeForBlock(const std::vector<CTransactionRef>& vtx, unsigned int nBlockHeight) EXCLUSIVE_LOCKS_REQUIRED(cs);
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bool CompareDepthAndScore(const Wtxid& hasha, const Wtxid& hashb) const;
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bool CompareMiningScoreWithTopology(const Wtxid& hasha, const Wtxid& hashb) const;
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bool isSpent(const COutPoint& outpoint) const;
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unsigned int GetTransactionsUpdated() const;
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void AddTransactionsUpdated(unsigned int n);
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@@ -245,21 +245,17 @@ class MempoolPackagesTest(BitcoinTestFramework):
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mempool1 = self.nodes[1].getrawmempool(False)
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assert set(mempool1).issubset(set(mempool0))
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assert parent_transaction in mempool1
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# Note: this test is brittle, because it relies on the relay sort order
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# of node0 to be based on ancestor count (so that the first 10
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# descendants of parent_transaction relay before the later ones).
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for tx in chain[:CUSTOM_DESCENDANT_LIMIT-1]:
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assert tx in mempool1
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for tx in chain[CUSTOM_DESCENDANT_LIMIT:]:
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assert tx not in mempool1
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for tx in mempool1:
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entry0 = self.nodes[0].getmempoolentry(tx)
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entry1 = self.nodes[1].getmempoolentry(tx)
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assert not entry0['unbroadcast']
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assert not entry1['unbroadcast']
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assert_equal(entry1['fees']['base'], entry0['fees']['base'])
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assert_equal(entry1['vsize'], entry0['vsize'])
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assert_equal(entry1['depends'], entry0['depends'])
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for tx in chain:
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if tx in mempool1:
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entry0 = self.nodes[0].getmempoolentry(tx)
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entry1 = self.nodes[1].getmempoolentry(tx)
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assert not entry0['unbroadcast']
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assert not entry1['unbroadcast']
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assert entry1["descendantcount"] <= CUSTOM_DESCENDANT_LIMIT
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assert_equal(entry1['fees']['base'], entry0['fees']['base'])
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assert_equal(entry1['vsize'], entry0['vsize'])
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assert_equal(entry1['depends'], entry0['depends'])
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# Test reorg handling
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# First, the basics:
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self.generate(self.nodes[0], 1)
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