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test: fix intermittent failure in rpc_invalidateblock.py

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node1 (with 24 blocks) causes node0 (with 6 blocks) to silently
reorg. so move the subtest to a point before the 20 blocks are
generated so that node1's state doesn't cause node0 to silently
reorg.
This commit is contained in:
stratospher
2025-07-14 14:46:07 +05:30
parent 7566b40bd2
commit 28416f367a
1 changed files with 8 additions and 8 deletions
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16
test/functional/rpc_invalidateblock.py
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@@ -102,6 +102,14 @@ class InvalidateTest(BitcoinTestFramework):
assert_equal(self.nodes[0].getblockchaininfo()['blocks'], 3)
assert_equal(self.nodes[0].getblockchaininfo()['headers'], 3)
# Reconsider the header
self.nodes[0].reconsiderblock(block.hash)
# Since header doesn't have block data, it can't be chain tip
# Check if it's possible for an ancestor (with block data) to be the chain tip
assert_equal(self.nodes[0].getbestblockhash(), blockhash_6)
assert_equal(self.nodes[0].getblockchaininfo()['blocks'], 6)
assert_equal(self.nodes[0].getblockchaininfo()['headers'], 7)
self.log.info("Verify that we reconsider all ancestors as well")
blocks = self.generatetodescriptor(self.nodes[1], 10, ADDRESS_BCRT1_UNSPENDABLE_DESCRIPTOR, sync_fun=self.no_op)
assert_equal(self.nodes[1].getbestblockhash(), blocks[-1])
@@ -128,14 +136,6 @@ class InvalidateTest(BitcoinTestFramework):
# Should report consistent blockchain info
assert_equal(self.nodes[1].getblockchaininfo()["headers"], self.nodes[1].getblockchaininfo()["blocks"])
# Reconsider the header
self.nodes[0].reconsiderblock(block.hash)
# Since header doesn't have block data, it can't be chain tip
# Check if it's possible for an ancestor (with block data) to be the chain tip
assert_equal(self.nodes[0].getbestblockhash(), blockhash_6)
assert_equal(self.nodes[0].getblockchaininfo()['blocks'], 6)
assert_equal(self.nodes[0].getblockchaininfo()['headers'], 7)
self.log.info("Verify that invalidating an unknown block throws an error")
assert_raises_rpc_error(-5, "Block not found", self.nodes[1].invalidateblock, "00" * 32)
assert_equal(self.nodes[1].getbestblockhash(), blocks[-1])