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[test] make tx6 child of tx5, not tx3, in rbf_tests

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There is no effect on the test results because tx3 and tx5 pay the say
fee, but this was the intended configuration, as the comment suggests.
This commit is contained in:
glozow
2022-08-11 12:48:04 +01:00
parent 0094ff3947
commit 49db42cdf5
1 changed files with 1 additions and 1 deletions
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2
src/test/rbf_tests.cpp
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@ -76,7 +76,7 @@ BOOST_FIXTURE_TEST_CASE(rbf_helper_functions, TestChain100Setup)
// Create a parent tx5 and child tx6 where both have very low fees
const auto tx5 = make_tx(/*inputs=*/ {m_coinbase_txns[2]}, /*output_values=*/ {1099 * CENT});
pool.addUnchecked(entry.Fee(low_fee).FromTx(tx5));
const auto tx6 = make_tx(/*inputs=*/ {tx3}, /*output_values=*/ {1098 * CENT});
const auto tx6 = make_tx(/*inputs=*/ {tx5}, /*output_values=*/ {1098 * CENT});
pool.addUnchecked(entry.Fee(low_fee).FromTx(tx6));
// Make tx6's modified fee much higher than its base fee. This should cause it to pass
// the fee-related checks despite being low-feerate.