feature_taproot: sample tx version border values more

Currently if the version 3 is selected for an otherwise
standard spender, the test will fail. It's unlikely but
possible, so change the test to update expectations and
sample more aggressively on border values to instigate
failures much quicker in the future if another version is
made standard.
This commit is contained in:
Greg Sanders
2025-06-30 17:00:24 -04:00
parent 6e5b67a370
commit 4be81e9746

View File

@@ -642,6 +642,9 @@ SIG_ADD_ZERO = {"failure": {"sign": zero_appender(default_sign)}}
DUST_LIMIT = 600
MIN_FEE = 50000
TX_MAX_STANDARD_VERSION = 3
TX_STANDARD_VERSIONS = [1, 2, TX_MAX_STANDARD_VERSION]
# === Actual test cases ===
@@ -1443,7 +1446,7 @@ class TaprootTest(BitcoinTestFramework):
while left:
# Construct CTransaction with random version, nLocktime
tx = CTransaction()
tx.version = random.choice([1, 2, random.getrandbits(32)])
tx.version = random.choice(TX_STANDARD_VERSIONS + [0, TX_MAX_STANDARD_VERSION + 1, random.getrandbits(32)])
min_sequence = (tx.version != 1 and tx.version != 0) * 0x80000000 # The minimum sequence number to disable relative locktime
if random.choice([True, False]):
tx.nLockTime = random.randrange(LOCKTIME_THRESHOLD, self.lastblocktime - 7200) # all absolute locktimes in the past
@@ -1535,8 +1538,7 @@ class TaprootTest(BitcoinTestFramework):
is_standard_tx = (
fail_input is None # Must be valid to be standard
and (all(utxo.spender.is_standard for utxo in input_utxos)) # All inputs must be standard
and tx.version >= 1 # The tx version must be standard
and tx.version <= 2)
and tx.version in TX_STANDARD_VERSIONS) # The tx version must be standard
msg = ','.join(utxo.spender.comment + ("*" if n == fail_input else "") for n, utxo in enumerate(input_utxos))
if is_standard_tx:
node.sendrawtransaction(tx.serialize().hex(), 0)