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feature_taproot: sample tx version border values more
Currently if the version 3 is selected for an otherwise standard spender, the test will fail. It's unlikely but possible, so change the test to update expectations and sample more aggressively on border values to instigate failures much quicker in the future if another version is made standard.
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@@ -642,6 +642,9 @@ SIG_ADD_ZERO = {"failure": {"sign": zero_appender(default_sign)}}
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DUST_LIMIT = 600
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MIN_FEE = 50000
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TX_MAX_STANDARD_VERSION = 3
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TX_STANDARD_VERSIONS = [1, 2, TX_MAX_STANDARD_VERSION]
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# === Actual test cases ===
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@@ -1443,7 +1446,7 @@ class TaprootTest(BitcoinTestFramework):
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while left:
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# Construct CTransaction with random version, nLocktime
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tx = CTransaction()
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tx.version = random.choice([1, 2, random.getrandbits(32)])
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tx.version = random.choice(TX_STANDARD_VERSIONS + [0, TX_MAX_STANDARD_VERSION + 1, random.getrandbits(32)])
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min_sequence = (tx.version != 1 and tx.version != 0) * 0x80000000 # The minimum sequence number to disable relative locktime
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if random.choice([True, False]):
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tx.nLockTime = random.randrange(LOCKTIME_THRESHOLD, self.lastblocktime - 7200) # all absolute locktimes in the past
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@@ -1535,8 +1538,7 @@ class TaprootTest(BitcoinTestFramework):
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is_standard_tx = (
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fail_input is None # Must be valid to be standard
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and (all(utxo.spender.is_standard for utxo in input_utxos)) # All inputs must be standard
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and tx.version >= 1 # The tx version must be standard
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and tx.version <= 2)
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and tx.version in TX_STANDARD_VERSIONS) # The tx version must be standard
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msg = ','.join(utxo.spender.comment + ("*" if n == fail_input else "") for n, utxo in enumerate(input_utxos))
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if is_standard_tx:
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node.sendrawtransaction(tx.serialize().hex(), 0)
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