Merge bitcoin/bitcoin#32841: feature_taproot: sample tx version border values more

4be81e9746 feature_taproot: sample tx version border values more (Greg Sanders)

Pull request description:

  Currently if the version 3 is selected for an otherwise standard spender, the test will fail. It's unlikely but possible, so change the test to update expectations and sample more aggressively on border values to instigate failures much quicker in the future if another version is made standard.

ACKs for top commit:
  maflcko:
    lgtm ACK 4be81e9746
  darosior:
    ACK 4be81e9746

Tree-SHA512: 53267a201aaa495bea9d624930a19e40af3633427b6715965f43b9e1a060b2c9f19c8b10c8168778349fa50715e44cb8e5e9d2ce477d5f324ca8ed28ff7996cd
This commit is contained in:
merge-script
2025-07-02 11:45:26 +01:00

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@@ -642,6 +642,9 @@ SIG_ADD_ZERO = {"failure": {"sign": zero_appender(default_sign)}}
DUST_LIMIT = 600
MIN_FEE = 50000
TX_MAX_STANDARD_VERSION = 3
TX_STANDARD_VERSIONS = [1, 2, TX_MAX_STANDARD_VERSION]
# === Actual test cases ===
@@ -1443,7 +1446,7 @@ class TaprootTest(BitcoinTestFramework):
while left:
# Construct CTransaction with random version, nLocktime
tx = CTransaction()
tx.version = random.choice([1, 2, random.getrandbits(32)])
tx.version = random.choice(TX_STANDARD_VERSIONS + [0, TX_MAX_STANDARD_VERSION + 1, random.getrandbits(32)])
min_sequence = (tx.version != 1 and tx.version != 0) * 0x80000000 # The minimum sequence number to disable relative locktime
if random.choice([True, False]):
tx.nLockTime = random.randrange(LOCKTIME_THRESHOLD, self.lastblocktime - 7200) # all absolute locktimes in the past
@@ -1535,8 +1538,7 @@ class TaprootTest(BitcoinTestFramework):
is_standard_tx = (
fail_input is None # Must be valid to be standard
and (all(utxo.spender.is_standard for utxo in input_utxos)) # All inputs must be standard
and tx.version >= 1 # The tx version must be standard
and tx.version <= 2)
and tx.version in TX_STANDARD_VERSIONS) # The tx version must be standard
msg = ','.join(utxo.spender.comment + ("*" if n == fail_input else "") for n, utxo in enumerate(input_utxos))
if is_standard_tx:
node.sendrawtransaction(tx.serialize().hex(), 0)