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Merge bitcoin/bitcoin#25820: [test] make tx6 child of tx5, not tx3, in rbf_tests
49db42cdf56be1a76ab381d37870aa45e17ab666 [test] make tx6 child of tx5, not tx3, in rbf_tests (glozow)
Pull request description:
A small overlooked oopsie from #25674.
There is no effect on the test results because tx3 and tx5 pay the same fee, but this was the intended configuration, as the comment suggests.
ACKs for top commit:
instagibbs:
ACK 49db42cdf5
darosior:
Github diff ACK 49db42cdf56be1a76ab381d37870aa45e17ab666. Should have catched this. :/
Tree-SHA512: 2f54337ac3edc38707115cde5b466a85b8a6ac0a0a507effa0e9fecb12c9be196ecd1b16702bc23ba617cfb6a3b5db27d3b71616b3c2dadb186c699c4609831e
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commit
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@ -76,7 +76,7 @@ BOOST_FIXTURE_TEST_CASE(rbf_helper_functions, TestChain100Setup)
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// Create a parent tx5 and child tx6 where both have very low fees
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const auto tx5 = make_tx(/*inputs=*/ {m_coinbase_txns[2]}, /*output_values=*/ {1099 * CENT});
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pool.addUnchecked(entry.Fee(low_fee).FromTx(tx5));
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const auto tx6 = make_tx(/*inputs=*/ {tx3}, /*output_values=*/ {1098 * CENT});
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const auto tx6 = make_tx(/*inputs=*/ {tx5}, /*output_values=*/ {1098 * CENT});
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pool.addUnchecked(entry.Fee(low_fee).FromTx(tx6));
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// Make tx6's modified fee much higher than its base fee. This should cause it to pass
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// the fee-related checks despite being low-feerate.
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